![]() We suggest that the analysis of this emotive framing may be a fruitful approach for sophisticated studies of argumentation beyond structural issues. Participants attended to the epistemic dimension, weighing evidence, and values about the choices, but the emotional framing took priority. The results suggest that the interactions between the group emotional tension and the evaluation of evidence drive a change toward a decision that would be emotionally acceptable for all participants. omnivorous diets (ODs) with a group of four preservice teachers. The goal of our study is to examine in which ways emotional tension frames the construction of arguments about vegetarian vs. We draw from Plantin, who proposed that emotions are mobilized as argumentative resources alongside knowledge. Our focus is on the dynamic interactions among emotions and scientific evidence. The relationship between argumentation and emotions is now drawing attention of researchers. In arguments about socio-scientific issues (SSI), a range of dimensions, besides scientific knowledge, including values, ethical concerns, cultural habits, or emotions, are mobilized. Argumentative discourse has a complexity that is not entirely captured by purely structural analyses. Which of the following is equivalent to sin 45⁰ ? a. Find the sum of secant 30 ° + cotangent 60 °. Find the product of tangent 45 ° and cotangent 45 °. ![]() REGION IV - A CALABARZON SCHOOLS DIVISION OF IMUS CITY IMUS NATIONAL HIGH SCHOOL BUKANDALA III IMUS CITY CAVITE 7. What is the exact value of cosine 45 ° ? a. Which of the following is equivalent to sin 45⁰? a. Find the sum of secant 30° + cotangent 60°. Find the product of tangent 45° and cotangent 45°. REGION IV-A CALABARZON SCHOOLS DIVISION OF IMUSĬITY IMUS NATIONAL HIGH SCHOOL BUKANDALA III IMUS CITY CAVITE 7. What is the exact value of cosine 45° ? a. opp tan A = adj tan 63⁰ = 5 11 tan 63⁰ b ( tan 63⁰ ) = 11 11 b = 11 Find LA LA and LB are complementary angles LA = 90 ° - LB LA = 90 ° -58 ° LA = 32 ° tan 63⁰ 11 b = 1.9696 b = 5.58 units Find c Side c is the hypotenuse and a is the opposite side of LA, then use SOH. LB = 90⁰ - 63⁰ LB = 27⁰ sin 58 ° = opp hyp sin 58⁰ = 27 27 sin 58 ° = b 27 ( 0.8480 ) = b b = 22.90 Find b Side b is the adjacent side and a is the opposite side of LA, then use TOA. Example : Find 2B cos 58⁰ = 27 27 cos 58 ° = a 27 ( 0.5299 ) = a a = 14.31 ZA and ZB are complementary angles, hence, LA and LB = 90⁰ Find b Side b is opposite side of LB and side c is the hypotenuse, so we will use sine. Solving a right triangle given the length of one leg and the measure of one acute angle. Example : b = ? 63 ° c = 27 - 58 ° a = ? C = ? B a = 11 Find a Side a is adjacent side of LB and side c is the hypotenuse, so we will use cosine. opp tan A = adj tan 63⁰ = 5 11 tan 63⁰ b(tan 63⁰) = 11 11 b= 11 Find LA LA and LB are complementary angles LA = 90° - LB LA = 90°-58° LA = 32° tan 63⁰ 11 b= 1.9696 b = 5.58 units Find c Side c is the hypotenuse and a is the opposite side of LA, then use SOH. ![]() LB =90⁰-63⁰ LB = 27⁰ sin 58° = opp hyp sin 58⁰ = 27 27 sin 58° = b 27(0.8480) = b b = 22.90 Find b Side b is the adjacent side and a is the opposite side of LA, then use TOA. Example: Find 2B cos 58⁰ = 27 27 cos 58° = a 27(0.5299) = a a = 14.31 ZA and ZB are complementary angles, hence, LA and LB = 90⁰ Find b Side b is opposite side of LB and side c is the hypotenuse, so we will use sine. Example: b=? 63° c=27 - 58° a =? C=? B a = 11 Find a Side a is adjacent side of LB and side c is the hypotenuse, so we will use cosine.
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